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A 0.5L of a solution is prepared by dissolving 120.9g of NaF in it. The molecular...

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A 0.5L of a solution is prepared by dissolving 120.9g of NaF in it. The molecular weight of NaF is 41.9g/mol). If I took 0.18

A 0.5L of a solution is prepared by dissolving 120.9g of NaF in it. The molecular weight of NaF is 41.9g/mol). If I took 0.18L of that solution and diluted it to 0.4, what is the molarity of the resulting solution? Answer to 3 significant figures Read about significant figures and rounding in the Helpful Resources page! .Do not include units when reporting your answer Use standard notation or scientific notation as accepted by blackboard e.g. 0.001 or 1E-3, not 1 x 10^-3

Answers

Molarity of Na F 120.9 wt x G M v(it) 41-9 0.5 = 5.77M O.18 x 5.77 = M2 X O-4 M2 = 0.18x5.77 O.4 =2.5965 = 2-60 M

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