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8 (a) पोग्य Volume of solution a 10.00ml mass of solution 2 10.0160 g 10.ooml density of solution - Volmass of solution Volume of solution 10,0160 g - 1:0016 glme Hence, the density of 0.150 m a solution is 100016 g/ml (6) Molarity of sstock solubich = 0: 150 M = 0.150 mallL Volume of stock asolution = 12 mass of sodium carbonate - Molarity X Volume X Molas 0.150 moll 4 x 14 x 108.9888 glmbl = 15.898 Hence, 18.8989 of sodium carbonate is in th of stock solution. g (c) Given 10.00 ml of the solution = 10.0100g 1.00 ml of the solution = 10.0160 los 2.00leeg 10.00 of 1000.00 ml of the solution = 1.00160x1600 g 12 of the solution = lool.60 Hence, mass of one lites of this above solution is lool.bog mass of Nago mass % of cos Ng CO3 = X100 mass of solution 15.898 g X100 T001.608 (d) - a eag ON bed - 1.587% is 1.587% Hence, mass % of Naga mmst
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