1 answer

=> 8-0.1UA O Sb. Which mole ratio (B/A) of the buffer components should (D/A) of the...

Question:

=> 8-0.1UA O Sb. Which mole ratio (B/A) of the buffer components should (D/A) of the buffer components should be used to crea
=> 8-0.1UA O Sb. Which mole ratio (B/A) of the buffer components should (D/A) of the buffer components should be used to create a buffer with ph more acid Homework: 6. Calculate the pH of the following buffers: 6a. 500.0 ml of a solution containing 0.400 mol NaF and on containing 0.400 mol NaF and 0.400 mol HF. (K = 6,6 x 104) OHPra - log (6.6x 10-4) = 3.18 66.500.0 ml of a solution containing 0.0400 mol NaF and 0.0400 mol HF. (K. = 6.6 x 10') More acidic - NaF & HF 0.0200 - NaF THE It doesnt have a conjugate 7. Calculate the % pH change of the buffers in problem 6 above when 0.020 mol of HNO, is added to them b. What can be concluded about a buffer ability to resist pH change according to the results above?

Answers

6.b) In this case the pH is also equal to pKa. pH = 3.18.

7.a) The pH change in buffer a and b is calculated:

ΔpH = log n Salt / n Acid = log (0.4 - 0.02 / 0.4 + 0.02) = 0.04

% pH change = 0.04 * 100 / 3.18 = 1.26%

Buffer B:

ΔpH = log (0.04 - 0.02 / 0.04 + 0.02) = 0.48

% pH change = 0.48 * 100 / 3.18 = 15.1%

7.b) There is a greater change in buffer B because it has less concentration of species in solution.

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