1 answer

5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle,...

Question:

5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle, and its speed is 5.0x 103 m/s. (a) Describe the protons motion in the magnetic field. (b) Calculate the radius of its path.
5. (15 pts) A proton enters a uniform 0.025 T magnetic field at a 90° angle, and its speed is 5.0x 103 m/s. (a) Describe the proton's motion in the magnetic field. (b) Calculate the radius of its path.

Answers

a)The force F on charged particle moving in a magnetic field is the cross product of velocity vector V and magnetic field B , if angle θ-900 the proton will move in circular motion due to the magnetic force b) the radius of the circular motion of proton -r mV m- proton mass-1.6726e- 027 kg V- proton velocity- 5.0e +03 m/s q1.6022e-019 C ;B-0.0250T we plug the values in hand while using the relation give us r 0.0020879 m mV

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