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![a) Construct mo diagram of Hat (linear) a) Linear structure - H o me HT=15° (3 cent te ze) Hals Bonding -> [mid H] [Group Or](https://i.imgur.com/nuT4F9E.png)
a) Construct mo diagram of Hat (linear) a) Linear structure - H o me HT=15° (3 cent te ze) Hals' Bonding -> [mid H] [Group Orbitala same phase) of Hydrogen 2000 MOMO E 15o anomag I BMO homo ①0 . н н н Central ht atom - H Group Orbitals of Hydrogen HGH 2 Center, Lelectron Only group Orbitals and central atown orbitals cuith the same symetry and similar Energy will start interact g orbitals interact while u orbitals in non bonding
(b) Construct MO diagram of cyclie Hay h found by J. J Thomsan (1911) Dah l E 26, 362 On 25; 30w H À This 3 o 13o1 aiii !! i ! E' 12-10 2 - 0 IH, Reduces Alte' 3 Mck) to i h .I AM O IL BMO BMD of to's fill Hat has ae (Bonding to de regio totally degenerate symmetric set of Combination Mo's formed from Combi- -nation of His Ad's y we can determine exactly how the As's should be combined to form the di proof to free and E Mo's using the projection operator Method. The Result of that Process I do ta (Ha that He ) - 0 t Malesa ta (2HA - He-He) - © The last e combination can be determi- - ned from the fact that each orbital most contribut equally across all set Also since First EMO contain I node 2/3 34€) = Ya CHo-HC ) QMA gives; A X most
Only the because lowest Mo Matters, Only that mo is occupied in Hat so the triangular version in achich pled mo es louler in energy is better.
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CU 7 o'o linear closely structure is most matches the toue geomety 3/3
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