## Answers

Idution : (a) To Calculate Noo, first we will Calcolate Navg. Naug at gft- 91111010, Naug at 29 ft- 6+6+6 6. Now Noo at g - Em.

Cs Cs Ca Narg 0.6 Where Ema 0.6, efficieny = 0.681x1x di&lo of high efficieny Us style - dojnut Safety Lammer Noo at g = 8.5 Assumed CCB = 1 (Bose hole dia Correction) Noo at 27'2 0.6x1x1 X0.85x6 C-1 (Sampler Cosceticu) (p=0.85 Rod Length Corretion 0.6 sil (6) (N.) 6o at 13 feet depth (+)60 = Noo 2000 (blfth | Eleptn) Ceffective Unit Weight) at 13 depta Nauga 5+5+7= 5.67, Noo= 0.6X1X1X0.8585:67 0.6 No=4.816 = (N.) 60 = 4.816 [2000 v (13) (127-62.47 pcp) = Assumed (Not given) 71432 - 7 =) (N.) 60 at 13 ft = 7

0.6 (1,60 = 1.7 rom (C) Doained friction angle from Soil Sample I SPT results are & Narg = 2+2+2 = 2 (Nico = 0.6X1X1X0:2542 As per Peck, hanson (1974) O'- 27.11° +0.3% (N) 60 - 0100054(14) Go o= 27,6 Aug @ from Soapon blw Cu BN, Cu value Coresponding to (Narg = 5+5+7)=5167 (4= 30 (Appoox.) N60 = 0.6X/X/X0.85x5.67 =hiblar of Su 015qu or 1:6 Nfield +15,4 Sur 41.6 (5.67)+154 = 24,472 Ich or Su= 2.1 (Noo)+17.6 - 2.1(4,8195) +17.6. su= 27.72 klach

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