## Answers

HClO_{2} is a weak acid and hence

pH = 1/2 pK_{a} - 1/2 log C_{H}^{+}

Or, 1/2 pK_{a} = pH + 1/2 logC_{H+}

Or, 1/2 pK_{a} = 3.40 + 1/2 log 0.25 (as C_{H+} = 0.25M)

Or, 1/2 pK_{a} = 3.40 +1/2 *(-0.602059)

= 3.40 - 0.30103

= 3.09897

Or, pK_{a} = 6.19794

Or, -log K_{a} = 6.19794

Or K_{a} = 10^{-6.19794}

^{ }= 6.34 * 10^{-7} (Answer)

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