Answers
1.Mass of crucible and cover=28.577g
mass of crucible and cover and alum before heating=30.577g
Therefore mass of alum= (30.577-28.577)g=2g
After 1st heating mass of crucible and cover and alum=29.719g
mass of alum after 1st heating (29.719-28.577)g=1.142g
mass lost (2-1.142)g=0.858g
After 2nd heating mass of crucible and cover and alum=29.679g
mass of alum after 2nd heating (29.679-28.577)g=1.102
mass lost (2-1.102)g=0.898g
After 3rd heating mass of crucible and cover and alum=29.649g
mass of alum after 3rd heating (29.649-28.577)g=1.072g
mass lost (2-1.072)g=0.928g
Molecular weight of alum =M=39.1+27+(322)+2
(16
4)+n
18=258.1+18n g/mol
total mass lost= 0.928 g
molecular weight of water=18 g
number of moles of water =(0.928/18)=0.05
mass of alum after third heating 1.072g
Molecular weight of dehydrated alum =258.1 g
number of moles of alum (1.072/258.1)=0.00415
0.00415 mol of alum contains 0.05 mol of water.
therefore 1 mol contains (0.05/0.00415)=12.03 mol of water.
therefore n=12.03 12
3.molecular weight of alum =258.1+18n=258.1+1218=474.1
molecular weight of sulphate group =(32+164)=96
theoretical percentage ==20%
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96 x 100 474.1
.
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