1 answer

2. 15 grams of CaCl is dissolved into 2 L of distilled water. (MW CaCl-110 g/mol)...

Question:

2. 15 grams of CaCl is dissolved into 2 L of distilled water. (MW CaCl-110 g/mol) a. What is the osmolarity of this solution?

2. 15 grams of CaCl is dissolved into 2 L of distilled water. (MW CaCl-110 g/mol) a. What is the osmolarity of this solution? b. What is the tonicity? e. What will happen to the shape of the cell if it is placed in this solution?

Answers

Ans 2 :

a)

Mol CaCl2 = mass /molar mass

= 15 g / 110.98 g/mol = 0.135 mol

each mol CaCl2 has three osmoles , so number of osmoles = 3 x 0.135 osmoles = 0.405 osmoles

Osmolarity = number of osmoles / volume (L)

= 0.405 osmoles / 2 L

= 0.203 osmol/L

b)

Since the membrane is not permeable to calcium and chlorine ions both so the tonicity of the solution is same as osmolarity i.e. 0.203 osmol/L

c)

The solution is hypotonic since it has less concentration of the solute particles in it. So when the cell is is placed in this solution , the cell swells up due to water absorption and hence it bursts if the wall is not rigid.

.

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