19. The solubility of PbBr2 is 0.427 g per 100.0 mL of solution at 25°C. Determine...

Question:

19. The solubility of PbBr2 is 0.427 g per 100.0 mL of solution at 25°C. Determine the value of the solubility product constant for this strong electrolyte. Lead(II) bromide does not react with water. a. 5.4 x 10-4 b. 2.7 x 10-4 c. 3.1 x 10-6 d. 1.6 x 10-6 e. 6.3 x 10-6 20. Calculate the pH of a solution that is 0.30 M in ammonia (NH3) and 0.20 M in ammonium chloride. Kb, NH3 = 1.76 x 10-5 ANS: 9.42

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