# 15 con in In a survery of 101 households, a Food Marketing Institute found that 41...

###### Question:

15 con in

In a survery of 101 households, a Food Marketing Institute found that 41 households spend more than $125 a week on groceries. Please find the 99.9% confidence interval for the true proportion of the households that spend more than$125 a week on groceries.

1. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.

Confidence interval =

2. Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

< p <

3. Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.

p =  ±±