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We are going to design the first order filter circuits with available no. of components to get the desired results..
Total components available = 5 i .e: Resistor rightarrow 100 ohm times 2 Inductor rightarrow 5 H times 1 capacitor rightarrow 100 uf times 2 Now, compare the cut - off frequency using different design techniques R - C circuit v_0/v_1 = v_sc/R + 1/sc = 1/1 + SRC The cut - off frequency for this RC - low pass filter Rightarrow fc = 1/2 pi RC = 10^6/ 2 pi 100 times 100 f c = 15.91 H_2 To achieve f r i_n = 1/2 pi R_max c_max connect e2 resistor in series R_max = R_1 + R_2 = 200 ohm connector 2 capacitor in parallel Rightarrow c_max = c_1 + c_2 = 200 H f Therefore f c_max = 1
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