1 answer

1. (sia)2BH 2. H2O2, NaOH 3. H2Cr04 4. SOCI2 5. H2C=CHCH2OH CECH Work out the above...

Question:

1. (sia)2BH 2. H2O2, NaOH 3. H2Cr04 4. SOCI2 5. H2C=CHCH2OH CECH Work out the above synthesis on a separate sheet of paper, a

1. (sia)2BH 2. H2O2, NaOH 3. H2Cr04 4. SOCI2 5. H2C=CHCH2OH CECH Work out the above synthesis on a separate sheet of paper, and then draw the organic product of reaction 3. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • Do not draw organic or inorganic by-products.

Answers

(sia) B4 -CECH -CH=CH-OH > Ho Noon Tauto menisculin -ch- CHO Thea- -coot HGO4 Isolla Doc H6Z0u-ch-oth Mo-CU-CH=Cl CH-C -cuc-c

Step1: substrate with reagents 1 and 2 yield 2-phenyl acetaldehyde. This reaction is the hydroboration reaction of alkyne

Step2: 2-phenyl acetaldehyde oxidised into corresponding acid by chromic acid

Step3: 2-phenylacetic acid converted to corresponding acid chloride by SOCl2

Step4: acid chloride and reagent 5 undergo esterification

.

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