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1. Given a vertical curve with: PVI station = 26+42.17PVI Elevation = 1642.91 feet Length =...

Question:

1. Given a vertical curve with: PVI station = 26+42.17PVI Elevation = 1642.91 feet Length = 947.00 feet Entrance grade (gl) =
1. Given a vertical curve with: PVI station = 26+42.17PVI Elevation = 1642.91 feet Length = 947.00 feet Entrance grade (gl) = -6.0% Exit grade (g2) = +1.2% Calculate the PVC station and elevation. • Calculate the PVT station and elevation. - Calculate the elevation at station 27+34.90. • Calculate the station and elevation of the high/low point.

Answers

ANSWER :PVC. g;= -60% PVT 92 = +1,2% PVI =26442.17 = 1642.91 1 Given length=947) ů station of PVC PVI - 2 = 426+42-17} - (247) PVL =2 (26+49, 115+ (247 PUT = 3115 67 PUT = 314 15.67 Elevation of PVT (_ * 22 100 Elu of PVI t 16 42.914 (947 1.2 . Х 100 = 1642Elevation of station 27+34.9 1: 12743097 - fadation of pozy (27 +34.97 - (21 4 68 +67} { x= 1566.281 --> elevatronx y) = (3-8

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