# 1) determine the number of milliliters of 4.75 M CBr2H2 solution that are needed to make...

###### Question:

1) determine the number of milliliters of 4.75 M CBr2H2 solution that are needed to make 65.5 ml of 1.05 M of that same solution.

2) determine the number of grams of CaCl2 that are needed to make a 0.355 liters of a 1.25 Molar solution.

3) 2Al(s) + 6HCl(g) → AlCl3(aq) + 3H2(g). Determine the grams of H2 produced 5.40 grams of Al.
This calculated value is the Theoretical yield. This Theoretical yield is to be used in problem 4.

4) For 5 points, 0.0400 grams of H2 are actually produced. Determine the Percent yield. Use the answer from problem 12 as the calculated Theoretical Yield.

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