Answers
1000 ml of a 1.25 (M) Caela = 1.25 moles of = 1.25 * 111 g . = 138.75 g OF, 0.355 L /355m of a 1.25 (4) Cacl2 = 138.75 X 355 1000 = 49.26 g B, 2 Al (s) + 6 Hel (g) → Aldiz (29) + 316 (9). According to the balanced equation, From 2 moles of Al 3 moles of this produced or, 2x26 252 g of AL gives 6 gem of H₂ 1 or 5.40g of Al gives 645.40 52 20.62 g of the 4. I can't understand the asking of the question: