## Answers

C2 My (8 1+30₂ (8) 2 CO₂ (g) + 2 H₂010) Al=-/411 KT/nd. Oll Cala (g) + 7/0₂ (9) 200₂ (G) + 34,00 All = -1560 kJ/mol. ② H₂ + ² H₂O(l) An = -285.8 kI/wel.

.
Adding (1) & (3) we get. of Cathy + m + 7 34,00) + 21€ a un'= -285.8+(-11) =-1696.8 kthol. - eq (M) - eq (2) we get. C2 441)+ 4₂0 Canol An°= -1696-8-6-1560) = -136. 8/KT/mol ® N2 +0₂2 ① N (G) +312 © 2U + O₂ NO 2NH₂ 2120 An= 180.5KT An=-91.8KT An =-483.6KT -1359KJ.

3x eq (3) - et 1x2 we get 34, +30 +2 NU; 240 +2, + 31, 41 = -3x 483-6-(-91.8) @ 302 + 2N937 6920+Nz A15=1353KJ. en(1) - eq(2) we get ① 2NH2 + O 2N0 + 34 Al=-180.5-(-91.8) = -88.7 kJ ef (4.82 + eq(3) X3 4NH3 + 20₂ + 64, +30₂ → YNO +62 + 64₂0 Ah = -88.782 YNH 2 GH 502 (9) TNO(g) + 6 120 (9) Au2-1628.2 KP +3x7-483-6)

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