You compress 0.5 moles of a gas at constant pressure from 4 liters to 1 liter while 2625 J of heat is removed, the temperature drops by 180.4 K, and Eth drops by 1875 J. How much work energy is added to the gas?

1 answer
Question:

You compress 0.5 moles of a gas at constant pressure from 4 liters to 1 liter while 2625 J of heat is removed, the temperature drops by 180.4 K, and Eth drops by 1875 J. How much work energy is added to the gas?

Answers

Answer:The work energy added to the gas isW = -72.48472 kJExplanation:For constant pressure processWork is given W = p×[tex](V_{f} - V_i)[/tex]However dH = m×[tex]c_{p} (T_2-T_1)[/tex] = 1875 JFor mass m, dQ = 2625 JThat is m×1875 = 2625 or m = 2625/1875 = 1.4 kgTherefore work doneper unit mass of gas is -W = p×(v₂ - v₁)but pv = RT therefore work done per unit mass = -R×(T₂ - T₁) = -R×ΔT andΔT = 180.4KWork done = -1.4×0.287×180.4 = -72.48472 kJ

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