Y=-x^2+20x-64 what is the max height

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Question:

y=-x^2+20x-64 what is the max height

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Answer:36Step-by-step explanation:The maximum height is the y-coordinate of the vertexgiven a quadratic in standard form : ax² + bx + c : a ≠ 0then the x-coordinate of the vertex is[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]y = - x² + 20x - 64 is in standard formwith a = - 1, b = 20 and c = - 64, hence[tex]x_{vertex}[/tex] = - [tex]\frac{20}{-2}[/tex] = 10substitute x = 10 into the equation for yy = - (10)² + 20(10) - 64 = 36 ← max height

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