# Write the equation in graphing form and the graph the shape. NO LINKS/ASSESSMENT!!16 + x^2 + y^2 - 8x - 6y = 0

1 answer

###### Question:

Write the equation in graphing form and the graph the shape. NO LINKS/ASSESSMENT!!

16 + x^2 + y^2 - 8x - 6y = 0

16 + x^2 + y^2 - 8x - 6y = 0

## Answers

Answer:see explanationStep-by-step explanation:The equation of a circle in standard form is(x - h)² + (y - k)² = r²where (h, k ) are the coordinates of the centre and r is the radiusGiven16 + x² + y² - 8x - 6y = 0 ( subtract 16 from both sides )x² + y² - 8x - 6y = - 16 ( collect x and y terms together )x² - 8x + y² - 6y = - 16Use the method of completing the squareadd ( half the coefficient of the x/y terms)² to both sidesx² + 2(- 4)x + 16 + y² + 2(- 3)y + 9 = - 16 + 16 + 9(x - 4)² + (y - 3)² = 9 ← in standard formwith centre (4, 3 ) and r = [tex]\sqrt{9}[/tex] = 3This is a circle with centre (4, 3 ) and radius 3

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