Will give the first answer brainliest. Picture attached.

1 answer
Question:

Will give the first answer brainliest. Picture attached.

Answers

Answer:2699.73661Ω or 2.697kΩExplanation:[tex]V=IR[/tex]So...[tex]R=\frac{V}{I}[/tex]So...[tex]\frac{12.3}{0.004556} = 2699.73661[/tex]ΩThis is the answer, but the resistance is much too high for a circuit like this

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