# Who knows how about to do this??

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Answer: [tex]f(4) = 2[/tex]Step-by-step explanation:1. [tex]f(n)=5n+8[/tex][tex]f(4)=\\\\f(-2)[/tex]Replace [tex]n[/tex] with [tex]4[/tex]; solve[tex]f(n)=5n+8\\\\f(n)=5(4)+8\\\\5(4)\\\\20+8\\\\28[/tex]Therefore, [tex]f(4) = 28[/tex]Replace [tex]n[/tex] with [tex]-2[/tex][tex]f(n)=5n+8\\\\f(n)=5(-2)+8\\\\5(-2)\\\\-10+8\\\\-2[/tex]Therefore, [tex]f(-2) = -2[/tex]2. [tex]f(n)=-2n+1[/tex][tex]f(10)=\\\\f(-1)=[/tex]Replace n with 10; solve[tex]f(n)=-2n+1\\\\f(n)=-2(10)+1\\\\-2(10)\\\\-20+1\\\\-19[/tex]

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