# Which statement is true of x2 + 8x - 6? 0 (x - 2) is a factor of the polynomial. (x + 2) is a factor of pe polynomial. (x – 4) is a factor of the polynomial. The polynomial is prime.

2 answers

###### Question:

Which statement is true of x2 + 8x - 6?

0 (x - 2) is a factor of the polynomial.

(x + 2) is a factor of pe polynomial.

(x – 4) is a factor of the polynomial.

The polynomial is prime.

0 (x - 2) is a factor of the polynomial.

(x + 2) is a factor of pe polynomial.

(x – 4) is a factor of the polynomial.

The polynomial is prime.

## Answers

Answer:x+2 and X-4 are the factorsStep-by-step explanation:

Let f(x) be x^2+8x-6x-2=0x=2f(2)=(2)^2+8(2)-6 = 4+16-6 = 20-6 = 14(x-2) is not a factor of f(x).x+2=0x=-2f(-2)=(-2)^2+8(-2)-6 = 4-16-6 = -18(x+2) is not a factor of f(x).x-4=0x=4f(4)= (4)^2+8(4)-6 = 16+32-6 = 10+32 = 42(x-4) is not a factor of f(x).Since none of the given factors are the factors of f(x), and the question states that one of the statements given above are true, the true statement is that the polynomial is prime.

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