What will happen when a piece of magnesium metal is dropped into a beaker containing a l M solution of copper(1) chloride? Mg2+ + 2e = Mg(9) P = - 2.37 VCu2+ + 2e → Cu(9) ° = + 0.34 V A. The magnesium will dissolve but nothing else will happen. B. The magnesium will dissolve and the copper will be deposited C. The copper will dissolve and the magnesium will be deposited D. The magnesium will dissolve and chloride gas will be produced E. There will be no reaction,​

1 answer
Question:

What will happen when a piece of magnesium metal is dropped into a beaker containing a l M solution of copper(1) chloride?
Mg2+ + 2e = Mg(9) P = - 2.37 V
Cu2+ + 2e → Cu(9) ° = + 0.34 V
A. The magnesium will dissolve but nothing else will happen.
B. The magnesium will dissolve and the copper will be deposited
C. The copper will dissolve and the magnesium will be deposited
D. The magnesium will dissolve and chloride gas will be produced E. There will be no reaction,​

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