# What the trinomial factor of this problem

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Answer:[tex]x^2-9x+20=(x-4)(x-5)[/tex]Step-by-step explanation:Factoring a TrinomialA second-degree trinomial can be expressed as:[tex]ax^2+bx+c[/tex]It can be factored, i.e., converted to a product instead of a sum of terms in several ways.We'll use the grouping method.Factor:[tex]x^2-9x+20[/tex]Split the second term into two terms:[tex]x^2-4x-5x+20[/tex]Factor x on the first two terms and -5 on the last two terms:[tex]x(x-4)-5(x-4)[/tex]Now factor out x-4:[tex](x-4)(x-5)[/tex]Thus:[tex]\mathbf{x^2-9x+20=(x-4)(x-5)}[/tex]

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