What is x in the similar triangles? Please help:)

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Question:

What is x in the similar triangles? Please help:)

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Answer:x = 18Step-by-step explanation:Since both right triangles are similar, therefore:[tex] \frac{2x - 6}{20} = \frac{39}{x + 8} [/tex]Cross multiply[tex] (2x - 6)(x + 8) = 39*20 [/tex][tex] 2x(x + 8) -6(x + 8) = 780 [/tex][tex] 2x^2 + 16x - 6x - 48 = 780 [/tex][tex] 2x^2 + 10x - 48 = 780 [/tex]Subtract 780 from both sides [tex] 2x^2 + 10x - 48 - 780 = 0 [/tex][tex] 2x^2 + 10x - 828 = 0 [/tex][tex] 2x^2 + 46x - 36x - 828 = 0 [/tex][tex] 2x(x + 23) - 36(x + 23) = 0 [/tex][tex] (x + 23)(2x - 36) = 0 [/tex]x + 23 = 0x = -23Or2x - 36 = 02x = 36x = 18

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