# What is the value of the rate constant for a second order reaction if the reactant conceretation drop sform 0.657 M to 0.0981 M in 17.0 s?

1 answer

###### Question:

What is the value of the rate constant for a second order reaction if the reactant conceretation drop sform 0.657 M to 0.0981 M in 17.0 s?

## Answers

Answer:The rate constant for a second order reaction isk = 0.51 dm-3 s-1.Explanation:In a regular second-order reaction the rate equation is given by v = k[A][B], if the reactant B concentration is constant then v = k[A][B] = k'[A], where k' the pseudo–first-order rate constant = k[B].Also 1/|A| = Kt + 1/|Ao|But Ao = 0.657 M andA = 0.0981 M alsot = 17.0 sTherefore1/| 0.0981 M| =K × 17.0 s + 1/| 0.657 M|→ 10.19/M = 17K + 1.52/M10.19/M - 1.52/M = 8.67/M = 17KK = 8.67M/17s = 0.51 dm-3 s-1.k = 0.51 dm-3 s-1.

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