What is the sum of the first 10 terms of the geometric sequence 4, -12, 36, -144

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What is the sum of the first 10 terms of the geometric sequence 4, -12, 36, -144

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The sum of the first 10 terms of the sequence 4, -12, 36, -144 is -59058The given geometric sequence is:4, -12, 36, -144The first term, a = 4The common ratio, [tex]r = \frac{-12}{4}\\r = -3[/tex]Since we are looking for the sum of the first 10 termsThe number of terms, n = 10The sum of the first n terms of a geometric sequence is given as:[tex]S_n = \frac{a(1-r^n)}{1-r} \\S_n = \frac{4(1-(-3)^{10}}{1-(-3)} \\S_n = \frac{4(1-59049)}{4} \\S_n = -59048[/tex]The sum of the first 10 terms of the sequence 4, -12, 36, -144 is -59058Learn more here: https://brainly.com/question/15626828

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