What is the solution set of the equation using the quadratic formula?x^2+2x+10=0A.) {−1+3i, −1−3i}B.) {−2+6i, −2−6i}C.) {2i, −4i}D.) {−1}

1 answer
Question:

What is the solution set of the equation using the quadratic formula?
x^2+2x+10=0
A.) {−1+3i, −1−3i}
B.) {−2+6i, −2−6i}
C.) {2i, −4i}
D.) {−1}

Answers

Answer:[tex] \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\ \frac{ - 2 \pm \sqrt{4 - 4(1)(10)} }{2} \\ = \frac{ - 2 \pm \sqrt{ - 36} }{2} \\ = \frac{ - 2 \pm 6i }{2} \\ - 1 \pm3i \\ so \: the \: answer \: is \: A[/tex]

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