What is the result of isolating x^2 in the equation below (x+1)^2+(y-8)^2=9
2 answers
Question:
what is the result of isolating x^2 in the equation below (x+1)^2+(y-8)^2=9
Answers
Answer:x² = 8 - (y - 8)² - 2xx² = 16y - y² - 2x - 56Step-by-step explanation:∵ (x + 1)² + (y - 8)² = 9∵ x² + 2x + 1 = 9 - (y - 8)²∴ x² = 9 - (y - 8)² - 2x - 1∴ x² = 8 - (y - 8)² - 2xOR:∵ x² = 8 - (y² -16y + 64) - 2x∴ x² = 8 - y² + 16y - 64 - 2x∴ x² = 16y - y² - 2x - 56
Answer: x² = 16y-y²-2x-56Step-by-step explanation:We have given the equation: (x+1)²+(y-8)²=9We have to solve it for x².So, the above equation is: (x+1)²+(y-8)²=9Open the square of the terms we get,x²+1+2x+y²+64-16y = 9x²+2x+y²-16y+65 = 9The equation in terms of x² is:x²= 9-2x-y²+16y-65x² = 16y-y²-2x-56 is the answer.
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