What is the minimum % relative error for a 0.5M NaOH solution? Assume the absolute error is +/- 0.1.
2 answers
Question:
What is the minimum % relative error for a 0.5M NaOH solution?
Assume the absolute error is +/- 0.1.
Assume the absolute error is +/- 0.1.
Answers
Answer: 20%Explanation:Relative error = Absolute error/actual value= 0.1/0.5 = 0.2Hence, Minimum % Relative error = 0.2 ×100%= 20%
Answer:20%Explanation:Let us take some important definitions of some terms in the question.What is an ABSOLUTE ERROR?. Absolute error is the difference between the expected value and the value you got from an experimental calculations or the approximations made. It can be represented mathematically in the equation (1) below; Absolute error= expected value - Approximated/measured value. ---------------------------------------------------------------------(1).What is A RELATIVE ERROR?. A relative error is the the ratio of absolute value to that of the exact value. This can be illustrated mathematically by the equation (2) below; Relative error= absolute error/exact value. --------------------------------------(3).From equation (2) the solutio to the question is; Relative error= absolute error/exact value.Relative error=[ 0.1/0.5] = 0.2.Relative error Percentage= 0.2×100= 20 Percent.
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