What is the equation of the line that passes through the point (5,-2) and has a slope of 6/5? Answer: Submit Answer attempt 1 out of

2 answers
Question:

What is the equation of the line that passes through the point (5,-2) and has a
slope of 6/5?
Answer:
Submit Answer
attempt 1 out of

Answers

Answer:y = 6/5x - 2Step-by-step explanation:use y = mx+ c m = slopec = y intercept y = 6/5x - 2

Given the point (5, -2), and slope = 6/5 Plug in the values into the slope-intercept formula: y = mx + bWhere:slope (m) = 6/5 b = y-interceptWe have to solve for the y-intercept. The y-intercept is the point on the graph where it crosses the y-axis. It is also the value of y when x = 0.y = mx + b-2 = 6/5(5) + b -2 = 6 + bSubtract 6 from both sides to solve for y-intercept, b: -2 – 6 = b -8 = b Therefore, the equation of the line that passes through (5,-2) and has a slope of 6/5 is: y = 6/5x - 8 Please mark my answers as the Brainliest if you find my explanations helpful :)

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