What is the equation of a line that passes through the point (4,2) and is perpendicular to the line whose equation is y = x3 - 1 Question 6 options: y = -3x + 14 y = x3 + 14 y = 3x + 23 y = -3x + 23 Question 7 (1 point) Question 7 Unsaved What is the equation of a line that passes through the point (4,2) and is parallel to the line whose equation is y = x3 - 1 Question 7 options: y = -3x + 14 y = x3 + 14 y = 3x - 23 y = -3x - 23

1 answer
Question:

What is the equation of a line that passes through the point (4,2) and is perpendicular to the line whose equation is y = x3
- 1
Question 6 options:
y = -3x + 14
y = x3
+ 14
y = 3x + 23
y = -3x + 23
Question 7 (1 point)
Question 7 Unsaved
What is the equation of a line that passes through the point (4,2) and is parallel to the line whose equation is y = x3
- 1
Question 7 options:
y = -3x + 14
y = x3
+ 14
y = 3x - 23
y = -3x - 23

Answers

Part A)the correct question  isWhat is the equation of a line that passes through the point (4,2) and is perpendicular to the line whose equation is y = (x/3)- 1we have thaty = (x/3)- 1  step 1find the slope mm=(1/3)we know thatif two lines are perpendicularso the slopes m1*m2=-1then (1/3)*m2=-1m2=-3step 2with m=-3 and the point (4,2) find the equation of the liney-y1=m*(x-x1)------> y-2=-3*(x-4)----> y-2=-3x+12----> y=-3x+14the answer part A) isy=-3x+14Part B)the correct question  isWhat is the equation of a line that passes through the point (4,2) and is parallel to the line whose equation is y = (x/3)- 1we have thaty = (x/3)- 1  step 1find the slope mm=(1/3)we know thatif two lines are parallelso the slopes m1=m2then m2=(1/3)step 2with m=(1/3) and the point (4,2) find the equation of the liney-y1=m*(x-x1)------> y-2=(1/3)*(x-4)----> y-2=(1/3)x-(4/3)y=(1/3)x-(4/3)+2-----> y=(1/3)x+(2/3)the answer part B) isy=(1/3)x+(2/3)using a graph toolsee the attached figure

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