What is the equation in polnt-slope form of the line passing through (-2, 1) and (4, 13)? (1 point) O a y-1=-2(x – 4) Ob y- 1 = 2(x + 2) ос y - 13 = -2(x + 2) Od y - 13 = 2(x + 4)

Answer:bStep-by-step explanation:The equation of a line in point- slope form isy - b = m(x - a)where m is the slope and (a, b) a point on the lineCalculate m using the slope formulam = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (4, 13)m = [tex]\frac{13-1}{4-(-2)}[/tex] = [tex]\frac{12}{4+2}[/tex] = [tex]\frac{12}{6}[/tex] = 2Using the point (- 2, 1 )y - 1 = 2(x - (- 2)) , that isy - 1 = 2(x + 2) → bUsing the point (4, 13)y - 13 = 2(x - 4) ← not one of the options