What is the distance covered by a free falling body during the first 3 seconds of its motion?ANSWER MY QUESTION WITH EXPLANATION ​

1 answer
Question:

what is the distance covered by a free falling body during the first 3 seconds of its motion?
ANSWER MY QUESTION WITH EXPLANATION ​

Answers

Distance s=ut+1/2 at^2 If it’s released then this becomes s=1/2at^2s=1/2 *9.81*9s=44.1 m

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