# What are the zeros of the quadratic function F(x)=6x^2+12x-7

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## Answers

Answer:x = -1 + sqrt(78)/6x = -1 - sqrt(78)/6Step-by-step explanation:Zeros are the x-values where the function is 0f(x) = 06x² + 12x - 7 = 0a = 6, b = 12, c = -7Using Quadratic formula:x = [-12 +- sqrt(12² - 4(6)(-7)]/2(6)x = [-12 +- sqrt(312)]/12x = [-12 + 2sqrt(78)]/12x = -1 +- sqrt(78)/6

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