What are the solutions to this quadric equation? X^2 + 13 = 8x + 37
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Question:
What are the solutions to this quadric equation? X^2 + 13 = 8x + 37
Answers
Answer:Step-by-step explanation:Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : x^2+13-(8*x+37)=0 Trying to factor by splitting the middle term 1.1 Factoring x2-8x-24 The first term is, x2 its coefficient is 1 . The middle term is, -8x its coefficient is -8 . The last term, "the constant", is -24 Step-1 : Multiply the coefficient of the first term by the constant 1 • -24 = -24 Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -8 . -24 + 1 = -23 -12 + 2 = -10 -8 + 3 = -5 -6 + 4 = -2 -4 + 6 = 2 -3 + 8 = 5 -2 + 12 = 10 -1 + 24 = 23 Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored Equation at the end of step 1 : x2 - 8x - 24 = 0
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