What are the solutions of this equation? x^ - x - 56 = 0

2 answers
Question:

What are the solutions of this equation? x^ - x - 56 = 0

Answers

Answer:y = 0Step-by-step explanation:

[tex]\large\bf{\underline{Solutions:}}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹8 , -7}[/tex]__________________________________________ [tex]\large\bf{\underline{Given\: equation :}}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹ x^2 -8x-56 }[/tex]__________________________________________[tex]\large\bf{\underline{Using\: middle\:term\: splitting}}[/tex][tex]\large\bf{Here, a = 1 , b = 1 \:and \:c= 56 }[/tex][tex]\large\bf{ ⟹ a\times c = 1\times56 =56}[/tex]Therefore we need two terms which on adding or subtracting with each other gives 56 and on multiplying gives 56__________________________________________[tex]\large\bf{\underline{By\: splitting \:the\:middle\:term:}}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x^2-8x+7x-56}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x(x-8)+7(x-8}[/tex]‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹(x-8)(x+7)}[/tex][tex]\large\bf{\underline{Hence}}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x-8=0}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x=0+8}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x=8}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎and ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x+7=0}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x=0-7}[/tex] ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎[tex]\large\bf{⟹x=-7}[/tex]

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