# What are the solutions of 12 – x2 = 0? x = 2 StartRoot 3 EndRoot and x = Negative 2 StartRoot 3 EndRoot x = 3 StartRoot 2 EndRoot and x = Negative 3 StartRoot 2 EndRoot x = 4 StartRoot 3 EndRoot and x = Negative 4 StartRoot 3 EndRoot x = 6 and x = –6

2 answers

###### Question:

What are the solutions of 12 – x2 = 0? x = 2 StartRoot 3 EndRoot and x = Negative 2 StartRoot 3 EndRoot x = 3 StartRoot 2 EndRoot and x = Negative 3 StartRoot 2 EndRoot x = 4 StartRoot 3 EndRoot and x = Negative 4 StartRoot 3 EndRoot x = 6 and x = –6

## Answers

Answer:±2 sqrt(3) = xStep-by-step explanation:12 -x^2 =0Add x^2 to each side12 -x^2+x^2 =0+x^212 = x^2Take the square root of each side±sqrt(12) = sqrt(x^2)We know that sqrt(ab) = sqrt(a) sqrt(b)±sqrt(4*3) = sqrt(x^2)±sqrt(4) * sqrt(3) = x±2 sqrt(3) = x

Answer:A) x = 2 StartRoot 3 EndRoot and x = Negative 2 StartRoot 3 EndRootStep-by-step explanation:

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