Two identical lead spheres with their centers 19 cm apart attract each other with a 0.30 μn force. find their mass.

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Question:

Two identical lead spheres with their centers 19 cm apart attract each other with a 0.30 μn force. find their mass.

Answers

[tex] m_{1} =m_2[/tex][tex] F_gravity [/tex] = 0.30 μn = [tex] (0.3)10^6[/tex]Using Newton's Equation for universal gravitation we can derive the masses[tex] F_{g} = G \frac{ m_{1} m_2}{d^2} [/tex][tex] F_{g} = G \frac{ 2m}{d^2}[/tex][tex]2m=\frac{d^2( F_{g}) }{G}[/tex][tex]m=\frac{d^2( F_{g}) }{2G}[/tex][tex]m=\frac{0.019^2( 0.3)(10^6)}{2 (6.673 (10^{-11})}[/tex][tex]m=\frac{0.019^2( 0.3)}{2 (6.673 (10^{-5})}[/tex][tex]m= 0.8114 kg[/tex]

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