This diagram shows two different forces acting on a skateboarder. Thecombined mass of the skateboard and the person is 65.2 kg. Based on thisinformation, what is the acceleration of the skateboarder?Air resistance = 55.20 NApplied force = 31.80siA. 0.36 m/s2 to the leftB. 1.46 m/s2 to the leftC. 0.36 m/s2 to the rightD. 1.47m/s2 to the right
2 answers
Question:
This diagram shows two different forces acting on a skateboarder. The
combined mass of the skateboard and the person is 65.2 kg. Based on this
information, what is the acceleration of the skateboarder?
Air resistance = 55.20 N
Applied force = 31.80
si
A. 0.36 m/s2 to the left
B. 1.46 m/s2 to the left
C. 0.36 m/s2 to the right
D. 1.47m/s2 to the right
combined mass of the skateboard and the person is 65.2 kg. Based on this
information, what is the acceleration of the skateboarder?
Air resistance = 55.20 N
Applied force = 31.80
si
A. 0.36 m/s2 to the left
B. 1.46 m/s2 to the left
C. 0.36 m/s2 to the right
D. 1.47m/s2 to the right
Answers
Answer:Option A. 0.36 m/s to the left Explanation:From the question given above, the following data were obtained:Force resistance (Fᵣ) = 55.2 NApplied force (Fₐ) = 31.8 NMass (m) = 65.2 kg.Acceleration (a) =? Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:Force resistance (Fᵣ) = 55.2 NApplied force (Fₐ) = 31.8 NNet force (Fₙ) =?Fₙ = Fᵣ – FₐFₙ = 55.2 – 31.8Fₙ = 23.4 N to the left Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:Mass (m) = 65.2 kg.Net force (Fₙ) = 23.4 N to the leftAcceleration (a) =? F = ma23.4 = 65.2 × aDivide both side by 65.2a = 23.4 / 65.2a = 0.36 m/sSince the net force acting on the skateboarder is to the left. Therefore, the acceleration of the stakeholder will also be towards the left (i.e 0.36 m/s to the left)
Answer:A. 0.36 m/s to the left
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