They told him that he was 30.8% too low in the boiling point he had just recorded. He had recorded a boiling point of 50 degrees C on his data sheet. what is the correct boiling point of the liquid he was working with in lab?
1 answer
Question:
they told him that he was 30.8% too low in the boiling point he had just recorded. He had recorded a boiling point of 50 degrees C on his data sheet. what is the correct boiling point of the liquid he was working with in lab?
Answers
Answer:36ºCExplanation:When you calculate percent it is important to determine the base value, because that is the denominator of your equation: [tex]Percent=\dfrac{\text{change or differece}}{base}\times 100[/tex]Here:difference = Correct boling point - Recorded boiling pointbase = Correct boiling point. Call it TbThe recorded boiling point is 50ºCPercent = 38% (below the correct boiling point)Subsitute and compute: [tex]38=\dfrac{Tb-50\ºC}{Tb}\times 100\\\\\\0.38Tb=Tb-50\ºC \\\\Tb+0.38Tb=50\ºC\\\\Tb=50\ºC/1.38\\\\Tb=36.23\ºC\approx 36\ºC[/tex] ← answer
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