These are 2 different questions 1) Suppose we have two consecutive ODD integers. If the smaller one is “x”, what would we call the larger one? 2) We are told there are two consecutive odd integers and the smaller one is 12 more than one-third of the larger one. Use your answer to problem 9 to write a clean equation and then find the integers?

There are two questions about consecutive odd integers1) (x + 2)2) The numbers are 19 and 211) We have two consecutive odd integers.Remember that the distance between any two consecutive odd numbers is 2.5 - 3 = 27 - 5 = 213 - 11 = 2etc.So if the smaller of the two odd numbers is x, then the larger one will be (x + 2).2) We have two consecutive odd numbers, let's write them as:(2*n + 1) and (2*n + 3)Where n is an integer number.We know that the smaller one is 12 more than one third of the larger one, so we have:(2*n + 1) = 12 + (2*n + 3)/3Now we can solve this for n2*n + 1 = 12 + (2/3)*n + 12*n - (2/3)*n = 12 + 1 - 1(4/3)*n = 12n = (3/4)*12 = 9n = 9Then the two consecutive odd integers are:(2*n + 1) = (2*9 + 1) = 19(2*n + 3) = (2*9 + 3) = 21If you want to learn more, you can read:https://brainly.com/question/15453368