The sum of two numbers is 52. The smaller number is 10 less than the larger number. What are the numbers?

2 answers
Question:

The sum of two numbers is 52. The smaller number is 10 less than the larger number. What are the numbers?

Answers

Answer:ta check the largest number to be x + 10 then the other number to be x then he quit x + 10 + x is equals to 52 collect the like terms x + x + 10 is equals to 52 2x + 10 is equals to 52 move channel to the equals sign so that it becomes 2 x is equals to 52 - 10 2 x is equals to 42 divide both sides by 2 x is equals to 21 so the largest number that was x + 10 now is 31 and the other number is 21

Answer:The numbers are 21 and 31.Step-by-step explanation:For this problem, we have two unknowns which we can call x and y. To solve for two unknowns, we will need two equations so we can use it to substitute one of the unknowns.We know that they add to 52 so we can write the equation:x + y = 52We also know that the smaller number is 10 less than the other one, so we can write the second equation:y - 10 = xNow we can use the second one to substitute for x in the first one and solve for y:(y-10) + y = 52Now we just need to solve it by simplifying and isolating the terms:y-10 + y = 52y+y - 10 + 10 = 52 +102y = 622y/2 = 62/2y = 31Now we can use either of the equations to solve for x now that we have y.31 - 10 = xx = 21The numbers are 21 and 31.Hope this helped!

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