The sum of three number 20. the sum of twice the first number, and 5 times the third number is 71. the difference between 4 times the first number and the scond number is 27. find the three numbers. Helllp
1 answer
Question:
the sum of three number 20. the sum of twice the first number, and 5 times the third number is 71. the difference between 4 times the first number and the scond number is 27. find the three numbers. Helllp
Answers
a = first numberb = second numberc = third numbera + b + c = 20 [1]2a + 5c = 71 [2]4a - b = 27 [3]Rearrange [2] and [3] to express in terms of a:c = (71 - 2a)/5 [2]b = 4a - 27 [3]Sub' these into [1], rearrange and solve:a + (4a - 27) + ((71 - 2a)/5) = 205a - 27 + (71 - 2a)/5 = 205(5a - 27) + 71 - 2a = 10025a - 135 + 71 - 2a = 10023a - 64 = 100a = 164/23Sub a-value into rearranged [2] and [3]:c = (71 - 2(164/23))/5= (1305/23)/5= 261/23b = 4(164/23) - 27= 656/23 - 27= 35/23
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