The sum of the two numbers is 42. The smaller number is 63 less than twice the larger number. Find both numbers. PLS ANSWER...... I NEED IT ASAP

1 answer
Question:

The sum of the two numbers is 42. The smaller number is 63 less than twice the larger number. Find both numbers.
PLS ANSWER...... I NEED IT ASAP

Answers

STEP 1:identify variables and equations x= larger number y= smaller numberFIRST EQUATION x + y= 42SECOND EQUATION y= 2x - 63STEP 2:substitute the y value in second equation in for y in first equation x + y= 42substitute y value from 2nd equation x + (2x - 63)= 42combine like terms3x - 63= 42add 63 to both sides3x= 105divide both sides by 3x= 35 larger number STEP 3:find y value; substitute step 2 x value into either original equation x + y= 4235 + y= 42subtract 35 from both sidesy= 7 smaller numberANSWER: larger number is x= 35; smaller number is y= 7.Hope this helps! :)

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