The specific heat of a certain type of metal is 0.128J/(g.°C). What is the final temperature if 305 J of hear is added to 28.8 g of this metal, initially at 20.0°C?

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Question:

The specific heat of a certain type of metal is 0.128J/(g.°C). What is the final temperature if 305 J of hear is added to 28.8 g of this metal, initially at 20.0°C?

Answers

Answer: Temperature final = 103 °CExplanation: To solve for final temperature we use the equation of heat:Q= mc∆T Next derive the equation to find final temperatureQ = mc(T final - T initial)Q / mc = T final - T initial Transpose T initial and change the sign so that T final will be left.T final = Q / mc + T initialSubstitute the values:T final = 305 J / 28.8 g x 0.128 J/(g°C) = 305 J / 3.6864 J/°C = 82.7 + 20.0°C = 103 °C final temperature.

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