The radius of circle a is 3 in the radius of circle b is 4 in greater than circle a circle c is 4 in greater than circle b the radius of circle d is 3 in less than the radius of circle c what is the area of all of the circles how many times greater than the area of circle a is the area of circle d

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Question:

The radius of circle a is 3 in the radius of circle b is 4 in greater than circle a circle c is 4 in greater than circle b the radius of circle d is 3 in less than the radius of circle c what is the area of all of the circles how many times greater than the area of circle a is the area of circle d

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Answer:Area of Circle A[tex]=9 \pi[/tex]Area of Circle B[tex]=49 \pi[/tex]Area of Circle C[tex]=121 \pi[/tex]Area of Circle D[tex]=64 \pi[/tex]The area of circle D is [tex]7\frac{1}{9}[/tex] times greater than the area of circle A.Step-by-step explanation:Circle AThe radius of circle A is 3 inr= 3 InchArea of Circle A[tex]=\pi r^2=3^2*\pi=9 \pi[/tex]Circle BThe radius of circle B is 4 inch greater than circle A.r= 4+Radius of circle A= 4+3 =7 InchArea of Circle B[tex]=\pi r^2=7^2*\pi=49 \pi[/tex]Circle CThe radius Circle C is 4 in greater than circle b.r= 4+Radius of circle B= 4+7 =11 InchArea of Circle C[tex]=\pi r^2=11^2*\pi=121 \pi[/tex]Circle DThe radius of circle D is 3 in less than the radius of circle C.r= Radius of circle C -3 = 11-3 =8 InchArea of Circle D[tex]=\pi r^2=8^2*\pi=64 \pi[/tex]Area of Circle A[tex]=9 \pi[/tex]Area of Circle D[tex]=64 \pi[/tex]Number of Times by which Area of Circle D is greater than Area of Circle A=[tex]\frac{64 \pi}{9 \pi} =7\frac{1}{9}[/tex]The area of circle D is [tex]7\frac{1}{9}[/tex] times greater than the area of circle A.

Answer:The areas are as followsa = 28.26 inches^2b = 153.86 inches^2c = 379.94 inches ^2d = 200.96 inches^2The area of circle d is greater than that of a by about 7 timesStep-by-step explanation:Please see the attached files for explanation

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