The price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour. At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same? pls pls pls

1 answer
Question:

The price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour. At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?
pls pls pls

Answers

Answer:2.174 hoursStep-by-step explanation:Let the number of hours be represented as: xThe price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour.$12.79 + $0.11 × x12.79 + 0.11x At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour. $13.29 - $0.12× x13.29 - 0.12xEquating both equations togetherStock A = Stock B12.79 + 0.11x = 13.29 - 0.12xCollecting like terms0.11x + 0.12x = 13.29 - 12.790.23x = 0.5x = 0.5/0.23x = 2.1739130435 hoursx = Approximately = 2.174 hoursIf the two rates​ continue, the number of hours that the prices of the two stocks will be the​ same is 2.174 hours

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