The power of a certain CD player operating at 120 V rms is 20.0 W. Assuming that the CD player behaves like a pure resistor, find (a) the maximum instantaneous power; (b) the rms current; (c) the resistance of this player. 31.20 .. In an L-R-C series

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Question:

The power of a certain CD player operating at 120 V rms is 20.0 W. Assuming that the CD player behaves like a pure resistor, find (a) the maximum instantaneous power; (b) the rms current; (c) the resistance of this player. 31.20 .. In an L-R-C series

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Answer:a.  [tex]40.0W[/tex]b.  [tex]0.167A[/tex]c.  [tex]720[/tex]ΩExplanation:Datapower average: [tex]P_{avr} =20.0W[/tex]operating voltage: [tex]V_{rms} =120V[/tex]a.The maximum instantaneous power: average power is one-half the maximum power.so the maximum instantaneous power is:[tex]=\frac{1}{\frac{1}{2} } *20.0W\\=2*20.0W\\=40.0W[/tex]b. To find current:   The formula to find rms current is:    [tex]I_{rms} =\frac{P_{avr} }{V_{rms} } \\I_{rms} =\frac{20.0W}{120V} \\I_{rms} =0.167A[/tex]c. To find the resistance of the player:    [tex]R=\frac{P_{avr} }{I_{rms} ^{2} } \\R=\frac{20.0W}{0.167^{2} }\\[/tex]    [tex]R=720[/tex]Ω

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