The perimeter of a rectangle is 156 inches. The length of the rectangle is five times its width. Find the area of the rectangle.

2 answers
Question:

The perimeter of a rectangle is 156 inches. The length of the rectangle is five times its width. Find the area of the rectangle.

Answers

Answer:Step-by-step explanation:Periemter is 2*L + 2*W Let x represent the width.  Then the length will be 5x  2*5x + 2x = 156in solve for x  10x + 2x = 156  12x = 156  x = 13in is the width  5x = 65in is the length  checking our answer 2*13in + 2*65in = 156in  

Answer:[tex][/tex][tex]\huge\mathfrak\purple{\:\:Answer\:\:}[/tex]Let us assume the length as 5x and breadth as xThen,Perimeter of a rectangle = 2(Length + breadth)→ 156inches = 2(5x + x)→ 156 = 2(6x)→ 156 = 12x→ [tex]\frac{156}{12}[/tex] = x[tex]\huge\color{cyan}\boxed {\colorbox{black}{x \: = \: 13}}[/tex]Breadth = x = 13inchLength = 5x = 5×13 = 65inchArea of a rectangle = Length × breadthArea = 65×13 inchesArea = 845 inches²

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